Physics

Physics

Problem

For a series R ⁣L ⁣CR\!L\!C circuit with R=40 ΩR=40\,\Omega, L=0.20 HL=0.20\,\text{H}, C=100 μFC=100\,\mu\text{F} and frequency 50 Hz50\,\text{Hz}, the magnitude of the impedance is closest to a) 71 Ω71\,\Omega b) 40 Ω40\,\Omega c) 51 Ω51\,\Omega d) 81 Ω81\,\Omega

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