Chemistry

Chemistry

Problem

For a certain gas-phase reaction, the forward activation energy is 150 kJ mol⁻¹ and the enthalpy change is ΔH=−40 kJ mol−1\Delta H = -40\,\text{kJ}\,\text{mol}^{-1}. What is the activation energy for the reverse reaction? a) 110 kJ mol−1110\ \text{kJ mol}^{-1} b) 150 kJ mol−1150\ \text{kJ mol}^{-1} c) 190 kJ mol−1190\ \text{kJ mol}^{-1} d) 40 kJ mol−140\ \text{kJ mol}^{-1}

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