Mathematics

Mathematics

Problem

If xn=1−2+3−4+5−6+⋯−2nn2+1+4n2−1x_n = \frac{1-2+3-4+5-6+\dots-2n}{\sqrt{n^2+1}+\sqrt{4n^2-1}} , then lim⁡n→∞xn\lim_{n \rightarrow \infty} x_n is equal to (a) −13-\frac{1}{3} (b) −23-\frac{2}{3} (c) 23\frac{2}{3} (d) 1

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