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Mathematics
Mathematics
Problem
If the lines
(
p
−
q
)
x
2
+
2
(
p
+
q
)
x
y
+
(
q
−
p
)
y
2
=
0
(p - q)x^2 + 2(p + q)xy + (q - p)y^2 = 0
(
p
−
q
)
x
2
+
2
(
p
+
q
)
x
y
+
(
q
−
p
)
y
2
=
0
are perpendicular to each other then :- (1)
p
=
q
p = q
p
=
q
(2)
q
=
0
q = 0
q
=
0
(3)
p
=
0
p = 0
p
=
0
(4)
p
p
p
and
q
q
q
can take any value
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