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Mathematics
Problem
An open box has a square base of side
x
x
x
cm and height
32
x
2
\frac{32}{x^2}
x
2
32
cm. Show that the surface area of the box is given by
S
=
x
2
+
128
x
S = x^2 + \frac{128}{x}
S
=
x
2
+
x
128
, and find the minimum possible surface area of the box. Show that the value you have found is a minimum.
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