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Problem Which of the following expressions is the derivative of h ( x ) = e 3 x ln x h(x)=\dfrac{e^{3x}}{\ln x} h ( x ) = ln x e 3 x for x > 0 x>0 x > 0 ?
a) e 3 x ( 3 ln x − 1 / x ) ln x \displaystyle \frac{e^{3x}\bigl(3\ln x-1/x\bigr)}{\ln x} ln x e 3 x ( 3 ln x − 1/ x )
b) e 3 x ( 3 ln x − 1 x ) ( ln x ) 2 \displaystyle \frac{e^{3x}\bigl(3\ln x-\tfrac1x\bigr)}{(\ln x)^2} ( ln x ) 2 e 3 x ( 3 ln x − x 1 )
c) e 3 x ( 3 ln x + 1 / x ) ( ln x ) 2 \displaystyle \frac{e^{3x}\bigl(3\ln x+1/x\bigr)}{(\ln x)^2} ( ln x ) 2 e 3 x ( 3 ln x + 1/ x )
d) 3 e 3 x ln x \displaystyle \frac{3e^{3x}}{\ln x} ln x 3 e 3 x
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