Chemistry

Chemistry

Problem

After oxygen atoms are balanced with H2O\text{H}_2\text{O} and hydrogen atoms with H+\text{H}^+, the reduction half-reaction MnO4−→Mn2+\text{MnO}_4^- \rightarrow \text{Mn}^{2+} still shows a charge of +7+7 on the left and +2+2 on the right. Which statement best justifies why 5 electrons must be added to the left side to complete the balancing? a) Five electrons are added to cancel the +5+5 charge introduced when 8 H+8\,\text{H}^+ ions are placed on the left during balancing. b) Manganese gains 5 electrons as its oxidation state decreases from +7+7 in MnO4−\text{MnO}_4^- to +2+2 in Mn2+\text{Mn}^{2+}, making the charges equal. c) Because there are five oxygen atoms in MnO4−\text{MnO}_4^-, five electrons must be added to balance the half-reaction. d) Since the Mn2+\text{Mn}^{2+} ion must lose 5 electrons to reach the +7+7 state of MnO4−\text{MnO}_4^-, the 5 electrons are written on the right side.

Browse the problem library