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Mathematics
Mathematics
Problem
Find the value of
∑
k
=
1
10
[
sin
(
2
π
k
11
)
−
i
cos
(
2
π
k
11
)
]
\sum_{k=1}^{10} \left[ \sin\left(\frac{2\pi k}{11}\right) - i \cos\left(\frac{2\pi k}{11}\right) \right]
∑
k
=
1
10
[
sin
(
11
2
π
k
)
−
i
cos
(
11
2
π
k
)
]
, where
i
=
−
1
i = \sqrt{-1}
i
=
−
1
.
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