Hatcher-Algebraic-Topology · Problem 2.2.17

Homology

Mathematics — Graph Theory · cellular-homology

Problem

Show the isomorphism between cellular and singular homology is natural in the following sense: A map f:X→Yf: X \to Y that is cellular — satisfying f(Xn)⊂Ynf(X^n) \subset Y^n for all nn — induces a chain map f∗f_* between the cellular chain complexes of XX and YY, and the map f∗:HnCW(X)→HnCW(Y)f_*: H_n^{CW}(X) \to H_n^{CW}(Y) induced by this chain map corresponds to f∗:Hn(X)→Hn(Y)f_*: H_n(X) \to H_n(Y) under the isomorphism HnCW≈HnH_n^{CW} \approx H_n.

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