Physics

Physics

Problem

A cube of unit volume contains 35×10735 \times 10^7 photons of frequency 101510^{15} Hz. If the energy of all the photons is viewed as the average energy being contained in the electromagnetic waves within the same volume, then the amplitude of the magnetic field is α×10−9\alpha \times 10^{-9} T. Taking permeability of free space μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7} Tm/A, Planck's constant h=6×10−34h = 6 \times 10^{-34} Js and π=227\pi = \frac{22}{7} , the value of α\alpha is [Adv. 2025]

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