Blundell Thermal Physics · Problem 11.4

Energy

Physics — Statistical Mechanics · partial-derivatives-polar-coordinates

Problem

In polar coordinates, x=rcos⁡θx = r\cos\theta and y=rsin⁡θy = r\sin\theta. The definition of xx implies that ∂x∂r=cos⁡θ=xr.(11.40)\frac{\partial x}{\partial r} = \cos\theta = \frac{x}{r}. \tag{11.40} But we also have x2+y2=r2x^2 + y^2 = r^2, so differentiating with respect to rr gives 2x∂x∂r=2r  ⟹  ∂x∂r=rx.(11.41)2x\frac{\partial x}{\partial r} = 2r \implies \frac{\partial x}{\partial r} = \frac{r}{x}. \tag{11.41} But eqns 11.40 and 11.41 imply that ∂x∂r=∂r∂x.(11.42)\frac{\partial x}{\partial r} = \frac{\partial r}{\partial x}. \tag{11.42} What's gone wrong?

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