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Mathematics
Mathematics
Problem
If
y
sec
x
+
tan
x
+
x
2
y
=
0
y \sec x + \tan x + x^2 y = 0
y
sec
x
+
tan
x
+
x
2
y
=
0
, then
d
y
d
x
=
\frac{dy}{dx} =
d
x
d
y
=
(a)
2
x
y
+
sec
2
x
+
y
sec
x
tan
x
x
2
+
sec
x
\frac{2xy + \sec^2 x + y \sec x \tan x}{x^2 + \sec x}
x
2
+
s
e
c
x
2
x
y
+
s
e
c
2
x
+
y
s
e
c
x
t
a
n
x
(b)
−
2
x
y
+
sec
2
x
+
sec
x
tan
x
x
2
+
sec
x
-\frac{2xy + \sec^2 x + \sec x \tan x}{x^2 + \sec x}
−
x
2
+
s
e
c
x
2
x
y
+
s
e
c
2
x
+
s
e
c
x
t
a
n
x
(c)
−
2
x
y
+
sec
2
x
+
y
sec
x
tan
x
x
2
+
sec
x
-\frac{2xy + \sec^2 x + y \sec x \tan x}{x^2 + \sec x}
−
x
2
+
s
e
c
x
2
x
y
+
s
e
c
2
x
+
y
s
e
c
x
t
a
n
x
(d) None of these
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