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Physics
Physics
Problem
A student derives the period of a simple pendulum as
T
=
2
π
g
L
T = 2\pi\sqrt{\dfrac{g}{L}}
T
=
2
π
L
g
, where
g
g
g
is acceleration due to gravity and
L
L
L
is the length of the pendulum. Identify the dimensional error in the expression and write the correct form of
T
T
T
.
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