Physics

Physics

Problem

Which expression gives the change in gravitational potential energy ΔU\Delta U of an object of mass mm lifted vertically by a distance Δy\Delta y near Earth’s surface where the acceleration due to gravity gg is approximately constant? a) ΔU=−mg Δy\Delta U = -mg\,\Delta y b) ΔU=12mg Δy\Delta U = \dfrac{1}{2}mg\,\Delta y c) ΔU=mg Δy\Delta U = mg\,\Delta y d) ΔU=−GmMEΔy\Delta U = -\dfrac{G m M_E}{\Delta y}

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