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Problem
## EXERCISE 2.2 Prove the following: 1.
3
sin
−
1
x
=
sin
−
1
(
3
x
−
4
x
3
)
,
x
∈
[
−
1
2
,
1
2
]
3 \sin ^{-1} x=\sin ^{-1}\left(3 x-4 x^{3}\right), x \in\left[-\frac{1}{2}, \frac{1}{2}\right]
3
sin
−
1
x
=
sin
−
1
(
3
x
−
4
x
3
)
,
x
∈
[
−
2
1
,
2
1
]
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