Physics

Problem

In an electron-diffraction arrangement using a nickel crystal (

d=0.091\,\text{nm}

), the second-order intensity maximum is observed at a glancing angle of

65^{\circ}

. a. (i) Calculate the potential difference

V_1

through which the electrons were accelerated. Take

h=6.626\times10^{-34}\,\text{J\,s}

m_e=9.11\times10^{-31}\,\text{kg}

and

e=1.6\times10^{-19}\,\text{C}

. b. (ii) If the accelerating potential is increased by

200\,\text{V}

while keeping all other conditions unchanged, determine the new glancing angle

\theta_2

at which the first-order maximum will now appear. c. (iii) Briefly justify whether the angular separation between successive maxima will increase or decrease as the accelerating potential is raised, keeping the crystal the same.

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