Show that the differential cross section for 2→2 scattering with piμ+pAμ→pfμ+pBμ in the rest frame of particle A can be written as
dΩdσ=64π2mA1[EB+Ef(1−∣pf∣∣pi∣cosθ)]−1∣pi∣∣pf∣∣M∣2,(5.54)
where θ is the angle between pi and pf, EB=(pf−pi)2+mB2 and Ef=pf2+mf2.