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Physics
Physics
Problem
For a particle executing simple harmonic motion of amplitude
A
A
A
, at which displacement from the mean position will the kinetic energy equal the potential energy? a)
x
=
A
2
x=\dfrac{A}{2}
x
=
2
A
b)
x
=
0
x=0
x
=
0
c)
x
=
A
2
x=\dfrac{A}{\sqrt{2}}
x
=
2
A
d)
x
=
A
3
x=\dfrac{A}{\sqrt{3}}
x
=
3
A
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