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Mathematics
Mathematics
Problem
Let
x
>
0
x>0
x
>
0
. a. (i) Prove that
arctan
x
+
arctan
(
1
x
)
=
π
2
\arctan x+\arctan\left(\dfrac{1}{x}\right)=\dfrac{\pi}{2}
arctan
x
+
arctan
(
x
1
)
=
2
π
. b. (ii) Using the result of part (i), evaluate
S
=
arctan
2
+
arctan
1
2
+
arctan
3
+
arctan
1
3
.
S=\arctan 2+\arctan\dfrac{1}{2}+\arctan 3+\arctan\dfrac{1}{3}.
S
=
arctan
2
+
arctan
2
1
+
arctan
3
+
arctan
3
1
.
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