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Problem
Passage - 2 (Question 63 to 65): If
f
:
(
0
,
∞
)
→
(
0
,
∞
)
f: (0, \infty) \rightarrow (0, \infty)
f
:
(
0
,
∞
)
→
(
0
,
∞
)
satisfy
f
(
x
f
(
y
)
)
=
x
2
y
a
f(xf(y)) = x^2 y^a
f
(
x
f
(
y
))
=
x
2
y
a
(
a
∈
R
a \in R
a
∈
R
), then Number of solutions of
2
f
(
x
)
=
e
x
2f(x) = e^x
2
f
(
x
)
=
e
x
is (a) 1 (b) 2 (c) 3 (d) 4
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