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Problem Let r = 3 θ r=3\theta r = 3 θ for 0 ≤ θ ≤ 2 0\le \theta\le 2 0 ≤ θ ≤ 2 . Which of the following gives d y d x \dfrac{dy}{dx} d x d y as a function of θ \theta θ ?
a) tan θ \displaystyle \tan\theta tan θ
b) sin θ + θ cos θ cos θ − θ sin θ \displaystyle \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta} cos θ − θ sin θ sin θ + θ cos θ
c) cos θ + θ sin θ sin θ − θ cos θ \displaystyle \frac{\cos\theta+\theta\sin\theta}{\sin\theta-\theta\cos\theta} sin θ − θ cos θ cos θ + θ sin θ
d) sin θ − θ cos θ cos θ + θ sin θ \displaystyle \frac{\sin\theta-\theta\cos\theta}{\cos\theta+\theta\sin\theta} cos θ + θ sin θ sin θ − θ cos θ
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