If ∣111abca3b3c3∣=(a−b)(b−c)(c−a)(a+b+c)\begin{vmatrix} 1 & 1 & 1 \\ a & b & c \\ a^3 & b^3 & c^3 \end{vmatrix} = (a-b)(b-c)(c-a)(a+b+c)…

Mathematics

Problem

If ∣111abca3b3c3∣=(a−b)(b−c)(c−a)(a+b+c)\begin{vmatrix} 1 & 1 & 1 \\ a & b & c \\ a^3 & b^3 & c^3 \end{vmatrix} = (a-b)(b-c)(c-a)(a+b+c), where a,ba, b and cc are all different, then the determinant ∣111(x−a)2(x−b)2(x−c)2(x−b)(x−c)(x−c)(x−a)(x−a)(x−b)∣\begin{vmatrix} 1 & 1 & 1 \\ (x-a)^2 & (x-b)^2 & (x-c)^2 \\ (x-b)(x-c) & (x-c)(x-a) & (x-a)(x-b) \end{vmatrix} vanishes when a. a+b+c=0a+b+c=0 b. x=13(a+b+c)x = \frac{1}{3}(a+b+c) c. x=12(a+b+c)x = \frac{1}{2}(a+b+c) d. x=a+b+cx = a+b+c

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