Mathematics

Mathematics

Problem

Calculate ∫(x−1)cos⁡4x dx\displaystyle \int (x-1)\cos 4x\,dx. a) 14(x−1)cos⁡4x+116sin⁡4x+C\dfrac{1}{4}(x-1)\cos 4x+\dfrac{1}{16}\sin 4x+C b) 14(x−1)sin⁡4x+116cos⁡4x+C\dfrac{1}{4}(x-1)\sin 4x+\dfrac{1}{16}\cos 4x+C c) 14(x−1)sin⁡4x−116cos⁡4x+C\dfrac{1}{4}(x-1)\sin 4x-\dfrac{1}{16}\cos 4x+C d) 14(x+1)sin⁡4x+116cos⁡4x+C\dfrac{1}{4}(x+1)\sin 4x+\dfrac{1}{16}\cos 4x+C

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