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Mathematics
Problem
A particle moves along a line with position given by
s
(
t
)
=
2
t
3
−
12
t
2
+
18
t
+
7
s(t)=2t^{3}-12t^{2}+18t+7
s
(
t
)
=
2
t
3
−
12
t
2
+
18
t
+
7
(meters) for
0
≤
t
≤
5
0\le t\le5
0
≤
t
≤
5
, where
t
t
t
is in seconds. Determine the time
t
t
t
at which the particle is farthest to the right of the origin on this interval. a)
t
=
1
t=1
t
=
1
b)
t
=
2
t=2
t
=
2
c)
t
=
5
t=5
t
=
5
d)
t
=
3
t=3
t
=
3
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