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Physics
Physics
Problem
An electric heater’s resistance is calculated using
R
=
V
2
P
R = \dfrac{V^{2}}{P}
R
=
P
V
2
. The potential difference and power are measured as
V
=
12.0
V
±
0.1
V
V = 12.0\,\text{V} \pm 0.1\,\text{V}
V
=
12.0
V
±
0.1
V
and
P
=
24.0
W
±
0.5
W
P = 24.0\,\text{W} \pm 0.5\,\text{W}
P
=
24.0
W
±
0.5
W
. Find the percentage uncertainty in
R
R
R
. a)
2.9
%
2.9\%
2.9%
b)
1.7
%
1.7\%
1.7%
c)
3.7
%
3.7\%
3.7%
d)
5.8
%
5.8\%
5.8%
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