General Relativity: An Introduction for Physicists · Problem 5.9

Special relativity revisited — Hobson, Efstathiou & Lasenby

Physics · 4-acceleration-orthogonal-velocity

Problem

Show that, in an inertial frame in which a particle's 3-acceleration a⃗\vec{a} is orthogonal to its 3-velocity u⃗\vec{u}, the particle's 4-acceleration is given by [aμ]=γu2(0,a⃗)[a^\mu] = \gamma_u^2(0, \vec{a}).
Intuitive explanation

When a particle's ordinary acceleration is perpendicular to its velocity, you're in a special geometric situation—the speed isn't changing, only direction. The key is to use the constraint that the 4-velocity has constant magnitude (uμuμ=−c2u^\mu u_\mu = -c^2) to relate the 4-acceleration components to the 3-acceleration, then exploit the orthogonality a⃗⊥u⃗\vec{a} \perp \vec{u} to show the time component vanishes. This perpendicularity is the crucial simplification that makes the 4-acceleration take this clean form.

Intuitive explanation

When a particle's ordinary acceleration is perpendicular to its velocity, you're in a special geometric situation—the speed isn't changing, only direction. The key is to use the constraint that the 4-velocity has constant magnitude (uμuμ=−c2u^\mu u_\mu = -c^2) to relate the 4-acceleration components to the 3-acceleration, then exploit the orthogonality a⃗⊥u⃗\vec{a} \perp \vec{u} to show the time component vanishes. This perpendicularity is the crucial simplification that makes the 4-acceleration take this clean form.

Related theory

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