Chemistry

Problem

The ground-state electron of a doubly ionised lithium atom (

\mathrm{Li}^{2+}

Z = 3

) is to be removed completely from the atom. a. (a) Calculate the ionisation energy per atom in

\text{eV}

. b. (b) Express the result of part (a) in

\mathrm{kJ\,mol}^{-1}

. (Avogadro number

N_A = 6.02 \times 10^{23}\,\text{mol}^{-1}

1\,\text{eV} = 1.60 \times 10^{-19}\,\text{J}

.) c. (c) By what factor is the value obtained in part (b) greater than the corresponding value for

\mathrm{He}^{+}

? (Use your answer to part (b) and quote the numerical factor only.)