Chemistry

Problem

The activation energy of

H_2 + I_2 \rightleftharpoons 2HI

in equilibrium for the forward reaction is

167 \text{ kJ mol}^{-1}

whereas for the reverse reaction is

180 \text{ kJ mol}^{-1}

. The presence of catalyst lowers the activation energy by

80 \text{ kJ mol}^{-1}

. Assuming that the reactions are made at

27^\circ C

and the frequency factor for forward and backward reactions are

4 \times 10^{-4}

and

2 \times 10^{-3}

respectively, calculate

K_C