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Mathematics
Mathematics
Problem
In quadrilateral
A
B
C
D
ABCD
A
B
C
D
,
∠
B
=
(
3
y
+
20
)
∘
\angle B = (3y + 20)^\circ
∠
B
=
(
3
y
+
20
)
∘
and
∠
D
=
(
7
y
−
40
)
∘
\angle D = (7y - 40)^\circ
∠
D
=
(
7
y
−
40
)
∘
. If
A
B
C
D
ABCD
A
B
C
D
is cyclic, calculate
∠
B
\angle B
∠
B
. a)
100
∘
100^{\circ}
10
0
∘
b)
65
∘
65^{\circ}
6
5
∘
c)
80
∘
80^{\circ}
8
0
∘
d)
68
∘
68^{\circ}
6
8
∘
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