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Mathematics
Problem
Solution of the quadratic equation
(
3
∣
x
∣
−
3
)
2
=
∣
x
∣
+
7
(3|x|-3)^2=|x|+7
(
3∣
x
∣
−
3
)
2
=
∣
x
∣
+
7
, which belongs to the domain of the function
y
=
(
x
−
4
)
x
y=\sqrt{(x-4)x}
y
=
(
x
−
4
)
x
is: (a)
±
1
9
,
±
2
\pm\frac{1}{9},\ \pm2
±
9
1
,
±
2
(b)
1
9
,
8
\frac{1}{9},\ 8
9
1
,
8
(c)
−
2
,
−
1
9
-2,\ -\frac{1}{9}
−
2
,
−
9
1
(d)
−
1
9
,
8
-\frac{1}{9},\ 8
−
9
1
,
8
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