Mathematics

Mathematics

Problem

The point PP on the curve r(t)=(1−2t)i^+t2j^+2e2(t−1)k^r(t) = (1 - 2t)\hat{i} + t^2\hat{j} + 2e^{2(t-1)}\hat{k} at which the tangent vector r′(t)r'(t) is parallel to the radius vector r(t)r(t) is a. (−1,1,2)(-1, 1, 2) b. (1,−1,2)(1, -1, 2) c. (−1,1,−2)(-1, 1, -2) d. (1,1,2)(1, 1, 2)

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