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Mathematics
Problem
The integral
∫
(
1
+
x
−
1
x
)
e
x
+
1
x
d
x
\int \left( 1 + x - \frac{1}{x} \right) e^{x + \frac{1}{x}} dx
∫
(
1
+
x
−
x
1
)
e
x
+
x
1
d
x
is equal to a.
(
x
−
1
)
e
x
+
1
x
+
C
(x-1)e^{x + \frac{1}{x}} + C
(
x
−
1
)
e
x
+
x
1
+
C
b.
x
e
x
+
1
x
+
C
xe^{x + \frac{1}{x}} + C
x
e
x
+
x
1
+
C
c.
(
x
+
1
)
e
x
+
1
x
+
C
(x+1)e^{x + \frac{1}{x}} + C
(
x
+
1
)
e
x
+
x
1
+
C
d.
−
x
e
x
+
1
x
+
C
-xe^{x + \frac{1}{x}} + C
−
x
e
x
+
x
1
+
C
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