Physics

Problem

When a particle of mass

m

is attached to a vertical spring of spring constant

k

and released, its motion is described by

y(t) = y_0 \sin^2 \omega t

, where '

y

' is measured from the lower end of unstretched spring. Then

\omega

is : a.

\frac{1}{2} \sqrt{\frac{g}{y_0}}

\sqrt{\frac{g}{y_0}}

\sqrt{\frac{g}{2y_0}}

\sqrt{\frac{2g}{y_0}}