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Mathematics
Mathematics
Problem
If
lim
x
→
0
(
tan
x
x
)
1
x
2
=
p
\lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p
lim
x
→
0
(
x
t
a
n
x
)
x
2
1
=
p
, then
96
log
e
p
96 \log_e p
96
lo
g
e
p
is equal to
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