Physics

Physics

Problem

14. A nucleus of polonium −218(21884Po)-218\left(\frac{218}{84} P o\right) emits an alpha particle (42α)\left(\frac{4}{2} \alpha\right). The next two elements in radioactive decay chain each emit a beta particle (0−1B−)\left(\frac{0}{-1} B^{-}\right). What would be the resulting nucleus after these three decays have occurred? A) 21482 Pb\frac{214}{82} \mathrm{~Pb} B) 21484Po\frac{214}{84} \mathrm{Po} C) 21485At\frac{214}{85} A t D) 22286Rn\frac{222}{86} R n

Browse the problem library