Physics

Physics

Problem

The time period TT of a simple pendulum may depend on its length ll, the mass of the bob mm and the acceleration due to gravity gg. Four students propose the following possible relationships: (a) T=2πlgT = 2\pi \sqrt{\dfrac{l}{g}} (b) T=2πmlgT = 2\pi \sqrt{\dfrac{m l}{g}} (c) T=2πlgmT = 2\pi \sqrt{\dfrac{l g}{m}} (d) T=2πmlgT = 2\pi \sqrt{\dfrac{m}{l g}} (i) Using dimensional considerations, identify the expression that can be correct. (ii) For the correct expression, calculate the time period when l=0.64 ml = 0.64\,\text{m} and g=9.8 m s−2g = 9.8\,\text{m s}^{-2}. a. (i) Identify the dimensionally correct expression. b. (ii) Calculate TT for l=0.64 ml = 0.64\,\text{m}, g=9.8 m s−2g = 9.8\,\text{m s}^{-2}.

Browse the problem library