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Mathematics
Mathematics
Problem
If
p
1
,
p
2
,
p
3
,
…
,
p
m
+
1
p_1, p_2, p_3, \dots, p_{m+1}
p
1
,
p
2
,
p
3
,
…
,
p
m
+
1
are distinct prime numbers. Then the number of factors of
p
1
n
p
2
p
3
…
p
m
+
1
p_1^n p_2 p_3 \dots p_{m+1}
p
1
n
p
2
p
3
…
p
m
+
1
is : (a)
m
(
n
+
1
)
m(n+1)
m
(
n
+
1
)
(b)
(
n
+
1
)
2
m
(n+1)2^m
(
n
+
1
)
2
m
(c)
n
⋅
2
m
n \cdot 2^m
n
⋅
2
m
(d)
2
n
m
2^{nm}
2
nm
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