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Mathematics
Problem
If the plane
x
2
+
y
3
+
z
4
=
1
\frac{x}{2} + \frac{y}{3} + \frac{z}{4} = 1
2
x
+
3
y
+
4
z
=
1
, cuts the coordinate axes in
A
,
B
,
C
A, B, C
A
,
B
,
C
, then the area of
△
A
B
C
\triangle ABC
△
A
B
C
is a.
29
\sqrt{29}
29
sq. units b.
41
\sqrt{41}
41
sq. units c.
61
\sqrt{61}
61
sq. units d. None of these
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