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Mathematics
Mathematics
Problem
In a
Δ
P
Q
R
\Delta PQR
Δ
P
QR
, if
3
sin
P
+
4
cos
Q
=
6
3 \sin P + 4 \cos Q = 6
3
sin
P
+
4
cos
Q
=
6
and
4
sin
Q
+
3
cos
P
=
1
4 \sin Q + 3 \cos P = 1
4
sin
Q
+
3
cos
P
=
1
, then the angle
R
R
R
is equal to [2012 AIEEE] a.
5
π
6
\frac{5\pi}{6}
6
5
π
b.
π
6
\frac{\pi}{6}
6
π
c.
π
4
\frac{\pi}{4}
4
π
d.
3
π
4
\frac{3\pi}{4}
4
3
π
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