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Mathematics
Mathematics
Problem
Let
k
(
x
)
=
{
x
2
−
9
x
−
3
,
x
≠
3
,
k
,
x
=
3.
k(x)=\begin{cases}\dfrac{x^{2}-9}{x-3}, & x\neq3,\\ k, & x=3.\end{cases}
k
(
x
)
=
⎩
⎨
⎧
x
−
3
x
2
−
9
,
k
,
x
=
3
,
x
=
3.
The value of
k
k
k
that makes
k
(
x
)
k(x)
k
(
x
)
continuous at
x
=
3
x=3
x
=
3
is a)
9
9
9
b)
6
6
6
c)
0
0
0
d)
3
3
3
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