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Mathematics
Mathematics
Problem
Find the point of intersection of the line
r
=
(
1
−
3
−
2
)
+
λ
(
4
1
−
6
)
\mathbf{r} = \begin{pmatrix} 1 \\ -3 \\ -2 \end{pmatrix} + \lambda \begin{pmatrix} 4 \\ 1 \\ -6 \end{pmatrix}
r
=
1
−
3
−
2
+
λ
4
1
−
6
and the plane
2
x
−
4
y
+
z
=
16
2x - 4y + z = 16
2
x
−
4
y
+
z
=
16
.
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