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Chemistry
Chemistry
Problem
At
40
∘
C
40^{\circ}\,\text{C}
4
0
∘
C
, the ion-product constant for water is
K
w
=
2.92
×
10
−
14
K_w = 2.92 \times 10^{-14}
K
w
=
2.92
×
1
0
−
14
. A solution at this temperature has
pH
=
5.80
\text{pH} = 5.80
pH
=
5.80
. Classify the solution as acidic, basic, or neutral.
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