Mathematics

Problem

\cos^{-1} x = \tan^{-1} x

, then a.

x^2 = \frac{\sqrt{5} - 1}{2}

x^2 = \frac{\sqrt{5} + 1}{2}

\sin(\cos^{-1} x) = \frac{\sqrt{5} - 1}{2}

\tan(\cos^{-1} x) = \frac{\sqrt{5} - 1}{2}