A student tries to solve the equation 0.3p−1.2=0.6 as follows:
0.3p−1.2=0.6⇒0.3p=1.8⇒p=6
Check carried out by the student:
0.3(6)−1.2=0.3⇒1.8−1.2=0.3⇒0.6=0.3(Hence p=6 is correct)
Answer the following:
(i) Locate and explain the error made in the checking process.
(ii) Perform a correct check for p=6.
(iii) Solve the equation once again to confirm the correct solution.
a. (i) …
b. (ii) …
c. (iii) …