A beam of light of uniform intensity and of a single wavelength strikes a screen in which there is a small circular hole of area A. Some of the light passes through, and then spreads by diffraction, as shown below.
[Figure: Diagram showing light beam passing through circular hole of area A in screen, then diffracting]
At the centre of the diffracted wave which reaches the centre of the screen, the intensity of the light is Io (intensity is the power per unit area). When the hole is made narrower, then the angular width of the beam increases, in such a way that for the diffracted beam, half the diameter of the hole will result in twice the width of the beam. If the diameter of the hole is halved, then what will be the new intensity at the centre of the diffracted beam?
A. Io/2
B. Io/4
C. Io/8
D. Io/16