Physics

Physics · modern-physics

Problem

(b) The isotropy of space implies that there is no preferred direction in the universe, i.e., that the laws of physics are the same in all directions. Use this to study the general coordinate transformations X,TX, T after setting x→−xx \rightarrow-x and x′→−x′x^{\prime} \rightarrow-x^{\prime} and conclude that A(v),D(v)A(v), D(v) are even functions of vv and B(v),C(v)B(v), C(v) are odd functions of vv. (Hint: the relative velocity vv is a number which is measured by the FF frame using v=dxdtv=\frac{d x}{d t}.) Given constants: 4. Lorentz Boost In Newtonian kinematics, inertial frames moving relatively to each other are related by the following transformations called Galilean boosts: x′=x−vtt′=t\begin{aligned} x^{\prime} & =x-v t \\ t^{\prime} & =t \end{aligned} In relativistic kinematics, inertial frames are similarly related by the Lorentz boosts: x′=11−v2/c2(x−vt)t′=11−v2/c2(t−vc2x)\begin{aligned} x^{\prime} & =\frac{1}{\sqrt{1-v^{2} / c^{2}}}(x-v t) \\ t^{\prime} & =\frac{1}{\sqrt{1-v^{2} / c^{2}}}\left(t-\frac{v}{c^{2}} x\right) \end{aligned} In this problem you will derive the Lorentz transformations from a minimal set of postulates: the homogeneity of space and time, the isotropy of space, and the principle of relativity. You will show that these assumptions about the structure of space-time imply either (a) there is a universal "speed limit" which is frame invariant, which results in the Lorentz boost, or (b) there is no universal "speed limit," which results in the Galilean boost. For simplicity, consider a one-dimensional problem only. Let two frames FF and F′F^{\prime} be such that the frame F′F^{\prime} moves at relative velocity vv in the positive- xx direction compared to frame FF. Denote the coordinates of FF as (x,t)(x, t) and the coordinates of F′F^{\prime} as (x′,t′)\left(x^{\prime}, t^{\prime}\right). The most general coordinate transformations between FF and F′F^{\prime} are given by functions X,TX, T, x′=X(x,t,v)t′=T(x,t,v)\begin{aligned} x^{\prime} & =X(x, t, v) \\ t^{\prime} & =T(x, t, v) \end{aligned} which we will refer to as the generalized boost. Context question: (a) The homogeneity of space and time imply that the laws of physics are the same no matter where in space and time you are. In other words, they do not depend on a choice of origin for coordinates xx and tt. Use this fact to show that ∂X∂x\frac{\partial X}{\partial x} is independent of the position xx and ∂T∂t\frac{\partial T}{\partial t} is independent of the time tt. (Hint: Recall the definition of the partial derivative.) Context answer: 证明题 Extra Supplementary Reading Materials: Analogously, we can conclude additionally that ∂X∂x\frac{\partial X}{\partial x} is independent of both xx and tt and ∂T∂t\frac{\partial T}{\partial t} is independent of xx and tt. It can be shown that X,TX, T may be given in the form X(x,t,v)=A(v)x+B(v)tT(x,t,v)=C(v)x+D(v)t\begin{aligned} X(x, t, v) & =A(v) x+B(v) t \\ T(x, t, v) & =C(v) x+D(v) t \end{aligned} where A,B,C,DA, B, C, D are functions of vv. In other words, the generalized boost is a linear transformation of coordinates.

Browse the problem library