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If
y
=
sec
−
1
(
x
+
1
x
−
1
)
+
sin
−
1
(
x
−
1
x
+
1
)
y = \sec^{-1} \left( \frac{\sqrt{x}+1}{\sqrt{x}-1} \right) + \sin^{-1} \left( \frac{\sqrt{x}-1}{\sqrt{x}+1} \right)
y
=
sec
−
1
(
x
−
1
x
+
1
)
+
sin
−
1
(
x
+
1
x
−
1
)
…
Mathematics
Problem
If
y
=
sec
−
1
(
x
+
1
x
−
1
)
+
sin
−
1
(
x
−
1
x
+
1
)
y = \sec^{-1} \left( \frac{\sqrt{x}+1}{\sqrt{x}-1} \right) + \sin^{-1} \left( \frac{\sqrt{x}-1}{\sqrt{x}+1} \right)
y
=
sec
−
1
(
x
−
1
x
+
1
)
+
sin
−
1
(
x
+
1
x
−
1
)
, then
d
y
d
x
=
\frac{dy}{dx} =
d
x
d
y
=
(a) 0 (b)
1
x
+
1
\frac{1}{\sqrt{x}+1}
x
+
1
1
(c) 1 (d) None of these
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