Mathematics

Mathematics

Problem

△ABC\triangle ABC is right-angled at CC and AC=BCAC = BC. Let CDCD be the altitude from CC to the hypotenuse ABAB. a. (i) Prove that △ACD≅△BCD\triangle ACD \cong \triangle BCD. b. (ii) Hence, show that AD=DBAD = DB. c. (iii) What can you conclude about point DD on the hypotenuse ABAB of △ABC\triangle ABC? State the result clearly.

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