Physics

Physics

Problem

Three point masses are glued to a lightweight plate at the positions shown (coordinates in meters): 0.50 kg0.50\,\text{kg} at (0,0)(0,0), 0.30 kg0.30\,\text{kg} at (0.60,0)(0.60,0), and 0.20 kg0.20\,\text{kg} at (0,0.60)(0,0.60). Calculate the rotational inertia of the system about an axis perpendicular to the plate and passing through the system’s center of mass. a) 0.18 kg⋅m20.18\,\text{kg}\cdot\text{m}^2 b) 0.080 kg⋅m20.080\,\text{kg}\cdot\text{m}^2 c) 0.13 kg⋅m20.13\,\text{kg}\cdot\text{m}^2 d) 0.33 kg⋅m20.33\,\text{kg}\cdot\text{m}^2

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