Physics

Problem

An electron, a doubly ionized helium ion (

\text{He}^{++}

) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths

\lambda_e

\lambda_{\text{He}^{++}}

and

\lambda_p

is : a.

\lambda_e > \lambda_{\text{He}^{++}} > \lambda_p

\lambda_e < \lambda_{\text{He}^{++}} = \lambda_p

\lambda_e > \lambda_p > \lambda_{\text{He}^{++}}

\lambda_e < \lambda_p < \lambda_{\text{He}^{++}}